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15(2z+1)cubed + 10( 2z+1)squared - 25 (2z+1) answer: 20z(2z+1)(3z+4) |
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idiot |
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i mean, i open a thread and this comes up O_o!1!1!1111!!!11!!~`~~one |
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no one asked you to respond to this idiotic topic. idiot :D |
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give me about 15 minutes |
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cubed means ³ right then its pretty easy really |
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anyone remembers how to use newtons binomium |
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ja |
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(a+b)^n=sum k->n ( (N NCR K) a^n * b^(k-n) ) or something |
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what's cubed? |
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tot de derde macht verheffen |
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z= anything |
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any value for Z would make that equation true Z can be any number |
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there is no equation |
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yes ther is: 15(2z+1)cubed + 10( 2z+1)squared - 25 (2z+1) = 20z(2z+1)(3z+4) |
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too bad i can't insert a picture of a whining little girl with the name JAroen on it. |
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and after solving it I saw that it doesnt matter the value of Z all the Z go and it ends like 0 = 0 |
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:D hahaha yes childrentalking: i can, just a minute |
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i don't think i can figure this one out now, even if i wanted to |
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z=0 equation: 0=0 ______________ z=1 equation: 420 = 420 ________________ z=2 .... |
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your answer is wrong nacmat |
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so, do you believe me or want a scan of my procedure? was I of help? |
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not at all but prove it |
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correct nacmat now i see you've got the wright answer |
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namat equals smart |
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according to nacmat. nacmat = nacmat. and that's all he needs to know |
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15(8z³+12z²+8z+1)+10(4z²+4z+1)-25(2z+1)=20z(2z+1)(3z+4) |
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equals poo |
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Yes, the answer given is correct. But why do you want to know? |
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because he's trying to show off with his insane mathzzzzkilzz |
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anyways i was able to solve this problem which is supposed to be "like" the first one 5(m+p)cu.-10(m+p)sq.-15(m+p)to the 4th =5(m+p)sq.[m+p-2-3(m+p)sq.] =5(m+p)sq. [m+p-2-3(m.sq+2mp +p.sq)] =5(m+p)sq. [m+p-2-3m.sq- 6mp-3p.sq] |
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i'm not trying to show off anything. i'm trying to figure out how to solve it stupid |
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www.mathgeeks.com |
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i dont know whether to slap you or thank you. i'll do both |
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i don't carre at all |
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you must've cared something. you did post in here. |
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holy mathemagics! |
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i want to build a house in this topic and live in it. |
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you will need to put down a tarp |
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Could someone please use the Frenet-Serret formulas to prove that r''' = [s'''+(kappa)^2(s')^3]T + [3(kappa)s's'' + (kappa)'(s')^2]N + (kappa)(tau)(s')^3B given kappa(t)= |r'(t) X r''(t)| / |r'(t)|^3 Thanks. |
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A "logical" vulcan asking a clingon for math help? |
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i realize we didnt cover this sort of problem in class so i'll make it my responsibility to kick my teacher in the nuts. thanks for the pic curbkeeper |
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