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need help with maths
 

offline sadist from the dark side of the moon on 2005-11-03 12:16 [#01768958]
Points: 8670 Status: Lurker



maybe there IS some mathematical genious here.

so, i have prove why

lim sinx/x = 1
x-->0

can somebody help me ?


 

offline redrum from the allman brothers band (Ireland) on 2005-11-03 12:24 [#01768966]
Points: 12878 Status: Addict



yeah. that's proved by calculus. that's all i can remember.
did it for my leaving cert though. piss easy stylez


 

offline redrum from the allman brothers band (Ireland) on 2005-11-03 12:24 [#01768967]
Points: 12878 Status: Addict



sorry, what i meant to write was: LAZY_TITLE


 

offline Combo from Sex on 2005-11-03 12:26 [#01768968]
Points: 7540 Status: Regular



it's kinda easy, cause sin(x) = x - x^3/3! + x^5/5! -... for
x newt to 0 so you got x/x=1 so limit is 1


 

offline Combo from Sex on 2005-11-03 12:27 [#01768970]
Points: 7540 Status: Regular



by the way you can find a proof in many books, but I don't
remember it, it's kinda classic though


 

offline sadist from the dark side of the moon on 2005-11-03 12:28 [#01768971]
Points: 8670 Status: Lurker



could you maybe search that site for it because my english
is not THAT good and i'll never find that


 

offline sadist from the dark side of the moon on 2005-11-03 12:30 [#01768975]
Points: 8670 Status: Lurker | Followup to Combo: #01768968



now i didn't expect something like that


 

offline ecnadniarb on 2005-11-03 12:31 [#01768978]
Points: 24805 Status: Lurker | Show recordbag



Easy


 

offline Combo from Sex on 2005-11-03 12:33 [#01768983]
Points: 7540 Status: Regular | Followup to ecnadniarb: #01768978



There's an easier way to prove it, but I don't remember. I
studied this 3 years ago.


 

offline sadist from the dark side of the moon on 2005-11-03 12:35 [#01768988]
Points: 8670 Status: Lurker | Followup to ecnadniarb: #01768978



thanks a bunch ecna !!

omfg! i never expected something like that... thought that
this could be made with just the information i got about
limits. you know like the cauchy law or the heine law...



 

offline Combo from Sex on 2005-11-03 12:42 [#01769000]
Points: 7540 Status: Regular



Haha it's easier.

lim(x->0) [sin(x)/x] = lim(x->0)[(sin(x)-sin(0))/(x-0)] =
d(sin(x))/dx (for x=0) = cos(0) = 1

=)


 

offline Combo from Sex on 2005-11-03 12:44 [#01769007]
Points: 7540 Status: Regular



well... if you are supposed to know that d(sin(x))/dx =
cos(x)

dunno, maybe you prove the derivation KNOWING lim(sin(x))/x


 

offline sadist from the dark side of the moon on 2005-11-03 13:24 [#01769038]
Points: 8670 Status: Lurker



combo: omg... i think i'll just leave that... that a bit too
much for me i guess


 

offline sadist from the dark side of the moon on 2005-11-03 13:41 [#01769064]
Points: 8670 Status: Lurker



maybe somehow easier ?? i cannot believe our teacher wants
to now something like that from us...


 

offline Dozer on 2005-11-03 14:14 [#01769095]
Points: 1234 Status: Regular | Followup to Combo: #01768968



use Taylor expansion of (sin x)/x


 

offline Dozer on 2005-11-03 14:17 [#01769097]
Points: 1234 Status: Regular | Followup to Dozer: #01769095



mmmmh maybe too complex lol


 

offline Dozer on 2005-11-03 14:20 [#01769105]
Points: 1234 Status: Regular



Combo: Taylor Expansion= Développement limité (si tu
connais lol :) )


 

offline thodob from Bergen (Norway) on 2005-11-03 14:24 [#01769111]
Points: 2143 Status: Lurker



Sounds like something a problem i had for 3. years ago.

But, sorry cant help you, my mathknowlegde is long gone...


 

offline Raz0rBlade_uk on 2005-11-03 14:25 [#01769112]
Points: 12540 Status: Addict | Show recordbag



carry the 1


 

offline thodob from Bergen (Norway) on 2005-11-03 14:27 [#01769114]
Points: 2143 Status: Lurker



L`Hopitals rule perhaps... as combo says..


 

offline Dozer on 2005-11-03 14:31 [#01769124]
Points: 1234 Status: Regular | Followup to Dozer: #01769105



well don't mind that's what you used in your post....I'm too
tired lol


 

offline _gvarek_ from next to you (Poland) on 2005-11-03 16:08 [#01769211]
Points: 4882 Status: Lurker



this is like a fucking nightmare come true.


 

offline vlari from beyond the valley of the LOLs on 2005-11-03 16:11 [#01769213]
Points: 13915 Status: Regular | Followup to thodob: #01769114



yeah, hospitals rule. they make sick people healthy lol


 

offline Fah from Netherlands, The on 2005-11-03 17:10 [#01769245]
Points: 6428 Status: Regular | Followup to vlari: #01769213



i wonder when it's my turn


 

offline vlari from beyond the valley of the LOLs on 2005-11-03 17:13 [#01769248]
Points: 13915 Status: Regular | Followup to Fah: #01769245



you're up next, son


 

offline lol on 2005-11-03 17:23 [#01769256]
Points: 12 Status: Regular



maths terrifies me, and i am ashamed of this. i have
forgotten almost every bit of maths i have ever known, i
think

maths :(


 

offline bogala from NYC (United States) on 2005-11-03 22:15 [#01769361]
Points: 5125 Status: Regular



Not being good at math cuts you out of so many interesting
jobs. It really sucks.


 

offline obara from Utrecht on 2005-11-03 22:21 [#01769363]
Points: 19377 Status: Regular



wow, you study maths in english ? impressive !


 

offline Combo from Sex on 2005-11-04 03:53 [#01769408]
Points: 7540 Status: Regular | Followup to Dozer: #01769105



of course, eveybody knows that ; ) read my first post


 

offline try-pod from Wimbledon, London (United Kingdom) on 2005-11-04 03:55 [#01769410]
Points: 136 Status: Lurker



My friend Ben just asked for help with maths as well. When
will mathmaticians do their own work and realise that I am
not a genius!


 

offline sadist from the dark side of the moon on 2005-11-04 11:01 [#01769734]
Points: 8670 Status: Lurker



i finally got it - the teacher wanted the way with the "d"
's...

d(sinx) etc.



 

offline OK on 2005-11-05 19:29 [#01771008]
Points: 4791 Status: Lurker



use definition of limit: delta epsilon thing. that is you
want to show that given a real number, m, you can show
another one, u. such that if |x| < u then |sinx/x - 1| < m.


wich ain't that easy.

the easiest way is by definition of derivative like combo
suggested.


 


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