 |
|
You are not logged in! F.A.Q Log in Register |
 |
|
 |
 Now online (1)belb ...and 191 guests Last 5 registered Oplandisks nothingstar N_loop yipe foxtrotromeo Browse members... |
 |
Members 8025Messages 2614087 Today 0 Topics 127542 |
|
|||||||||
| |||||||||
|
|
can u please help me solve this 1 + 1/x = 6/x2 (those who have nothing to say pertaining to this subject matter please keep away. i'm not in the mood) |
||||||||
|
|
|||||||||
| |||||||||
|
|
x (1+1) = 6 x/2 = 6/2 x=3. What year are you in? |
||||||||
|
|
|||||||||
| |||||||||
|
|
1 + 1/3 does not equal 6/6 |
||||||||
|
|
|||||||||
| |||||||||
|
|
x=2, what year are YOU in? |
||||||||
|
|
|||||||||
| |||||||||
|
|
winner! |
||||||||
|
|
|||||||||
| |||||||||
|
|
i don't get it |
||||||||
|
|
|||||||||
| |||||||||
|
|
i'm taking a practice final exam online. i'm currently trying to finish my associates, for nursing. in that particular problem the multiple choices are a {2,3) b {-1/3, 1/2} c {-3,2} d {-2,3} thanks though you're more than welcome to give it another try. i stopped at x(x+1) =6 then i was trying to figure out how they got to those answers |
||||||||
|
|
|||||||||
| |||||||||
|
|
I don't understand what's up with the ordered pairs if it's only one variable. |
||||||||
|
|
|||||||||
| |||||||||
|
|
you're solving for x. so i'm assuming theres more than one answer when you factor it out after using the LCD. |
||||||||
|
|
|||||||||
| |||||||||
|
|
do you mean 1 + 1/x = 6 / 2x ? |
||||||||
|
|
|||||||||
| |||||||||
|
|
everyone will help you cause we're all lonely boys and we think you'll be our girlfriend if we help |
||||||||
|
|
|||||||||
| |||||||||
|
|
whatever no biggy. i guess i'll just post that question at alg.com i just didnt want have to wait for them to respond an hour later. |
||||||||
|
|
|||||||||
| |||||||||
|
|
the process goes: x can't be two different things, otherwise it would be called something else for one of them. such as 'y' |
||||||||
| Attached picture | |||||||||
|
|||||||||
|
|
|||||||||
| |||||||||
|
|
no x sq. earth. have fun |
||||||||
|
|
|||||||||
| |||||||||
|
|
yeah the only time X has two values is when you're solving for an absolute value like |-3| |
||||||||
|
|
|||||||||
| |||||||||
|
|
i just clarrified it mapz try again and tell me what u get and most importantly how u got it if youre that bored. i want to thank everybody for posting. i guess this thread doesnt consist of entirely immature folks :) |
||||||||
|
|
|||||||||
| |||||||||
|
|
okay, then it's 2 or -3 |
||||||||
|
|
|||||||||
| |||||||||
|
|
you wanna show via ms paint :)? |
||||||||
|
|
|||||||||
| |||||||||
|
|
c {-3,2} |
||||||||
| Attached picture | |||||||||
|
|||||||||
|
|
|||||||||
| |||||||||
|
|
yo, multiply through by x^2, then collect on one side: x^2 + x - 6 = 0 factor (x+3)(x-2) = 0 x is -3 or +2 |
||||||||
|
|
|||||||||
| |||||||||
|
|
ah forgot to make the problem a quadratic eq. touch'e maps i commend you. where do i send u ur check :) |
||||||||
|
|
|||||||||
| |||||||||
|
|
woohoo! |
||||||||
|
|
|||||||||
| |||||||||
|
|
you guys are so cute |
||||||||
|
|
|||||||||
| |||||||||
|
|
just be thankful i didnt have a question on completing the squares or you'd probably run out of ink |
||||||||
|
|
|||||||||
| |||||||||
|
|
i'm gonna go spin some records send me an invitation to the wedding |
||||||||
|
|
|||||||||
| |||||||||
|
|
S A F E T Y DANCE! |
||||||||
|
|
|||||||||
| |||||||||
|
|
Ceri is hiding in shame. |
||||||||
|
|
|||||||||
| |||||||||
|
|
its ok he only has to deal with binary & hex |
||||||||
|
|
|||||||||
| |||||||||
|
|
x (1+1) = 6 x=3? LOL x/2 = 6/2 x=3? LOL That's pretty whack yo. |
||||||||
|
|
|||||||||
| |||||||||
|
|
Oh wait...laugh out loud at myself. The first one does equal three. |
||||||||
|
|
|||||||||
| |||||||||
|
|
oh wait.. so does the second :) |
||||||||
|
|
|||||||||
| |||||||||
|
|
YOU will NEVER use that stuff in the real world |
||||||||
|
|
|||||||||
| |||||||||
|
|
Or, in case you come across a quadratic polynomial that you can't factor as easily: You have: a*x^2 + b*x + c = 0. You do: x^2 + (b/a)*x + c/a = 0 x1 = - b/2a + squareroot((b/2a)^2 - c/a) x2 = - b/2a - squareroot((b/2a)^2 - c/a). If D=(b/2a)^2-c/a is zero, then x1=x2, which means there's only one solution. If D is real and not zero, then there are two solutions, which are real only if D>0. You probably won't have to deal with complex numbers, so that's all you need to know: D>0, two solutions. D=0, one solution. D<0, no real solution. So in your case: a=1, b=1, c=-6. D=1/4+6= (2 1/2)^2 x1 = - 1/2 + sqrt(6 1/4) = 2 x2 = - 1/2 - sqrt(6 1/4) = -3. |
||||||||
|
|
|||||||||
| |||||||||
|
|
what do you know about the real world? |
||||||||
|
|
|||||||||
| |||||||||
|
|
not much im only 29 years old |
||||||||
|
|
|||||||||
| |||||||||
|
|
hair falling out yet? :) |
||||||||
|
|
|||||||||
| |||||||||
|
|
no, but ive notived a few white ones slipping in fact: your hair chromosomes are from your mothers dads side so... whatever kind of hair your grandpa (genetic grandpa) has, you have a high probability of having the same in my case: my grandpa has a full head of hair, and gets it crew-cut |
||||||||
|
|
|||||||||
| |||||||||
|
|
i thought that too, until the inevitable "exception that proves the rule" curse struck me down :( *slaps own head several times* |
||||||||
|
|
|||||||||
| |||||||||
|
|
do you also inherit the same haircut? |
||||||||
|
|
|||||||||
| |||||||||
|
|
can't you even do a nice thin comb-over? |
||||||||
|
|
|||||||||
| |||||||||
|
|
i had the wifey shave my head at 1/8" for like 3 years grandpa proably gets his cut at 1/2" now im growing it out |
||||||||
|
|
|||||||||
| |||||||||
|
|
Going back a ways: Heheh, no it doesn't x/2 = 6/2 x=3? Okay then does 3/2 = 6/2 No. |
||||||||
|
|
|||||||||
| |||||||||
|
|
im really confused now! :) |
||||||||
|
|
|||||||||
| |||||||||
|
|
2+2=5 |
||||||||
| Attached picture | |||||||||
|
|||||||||
|
|
|||||||||
| |||||||||
|
|
i bet ceri likes radiohead |
||||||||
|
|
|||||||||
| |||||||||
|
|
i bet recycle likes: kid-a amnesiac live recordings and hail to the theif |
||||||||
|
|
|||||||||
| |||||||||
|
|
( i think you clicked the wrong comment when intending reply ) |
||||||||
|
|
|||||||||
| |||||||||
|
|
Very funny. The lack of brackets confused me. I like Radiohead's stuff up to Ok Computer (I like Iron Lung and How am I driving, but they were both recorded before OK computer was released). Kid A etc. have been pretty mediocre IMO. |
||||||||
|
|
|||||||||
| |||||||||
|
|
Oh shit, i remember maths. |
||||||||
|
|
|||||||||
| |||||||||
|
|
69 |
||||||||
|
|
|||||||||
|
Messageboard index
|
|||||||||
