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 Now online (2)big recycle ...and 653 guests Last 5 registered Oplandisks nothingstar N_loop yipe foxtrotromeo Browse members... |
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Members 8025Messages 2614121 Today 4 Topics 127542 |
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the mass reactant of a chemical reaction given the moles or grams? |
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*explodes* |
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given that that should be basic arithmatic, I think we all could do that. |
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if i give you a problem you can work it out for me then, right? i know how to do it. i just want to know how many people here have a brain they tend to you use from time to ime. |
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I remember chemisty courses. Aren't you just converting energy to mass? There would be a formula for that, and then you just plug in the amounts of energy in each chemical you start out with. Energy is conserved, so you should be able to convert to a mass (grams) and work from there. I don't remember much of moles, besides 6.07 x 10^24 or something like that. |
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I suck at math |
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you dont need a formula. u just need the periodic table, and the problem ofcoarse. |
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Sodium reacts with oxygen to produce sodiume oxide. 4Na(s) + O2(g) ---> 2Na2O(s) a. How many grams of Na2O are produced when 2.5 moles of Na react? b. If you have 18.0g of Na, how many grams of O2 are required for reaction? c. How many grams of O2 are needed in a reaction that produces 75.0g of Na2O? bon appetite |
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six |
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but isn't there a formula to convert the energy that is part of any chemical compostion, into mass once a reaction has taken place? I mean, if you combined one mole of Co, and one mole of Ca, does the weight depend soley on the mass of both summed, or does the reaction alter that to an extent? is it just straight sums? |
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blarr blarr blarr blarr blarr blarr blarr blarr blarr blarrblarr blarr blarr blarrblarr blarrblarr blarr blarr blarrblarr blarrblarr blarrblarr blarrblarr blarrblarr blarr blarr blarr blarr blarr blarr blarr blarr blarrblarr blarrblarr blarr blarr blarr blarr blarr blarr blarr blarr blarr blarr blarr blarr blarrblarr blarrblarr blarr blarr blarr blarr blarrblarr blarrblarr blarr blarr blarr blarr blarr blarr blarrblarr blarr blarr blarr |
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ok, didn't see new post: a) can't get it. b) 4.5 c) 75 |
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you only need the periodic table so you can locate the atomic mass of the particular product you're looking for. in this case you'll be working with Sodium and Oxygen. i'll give you the mass Sodium 23g Oxygen 16g |
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a) is the easiest question because the mole of one of the products is already given b) no c) no |
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alright, I tried and failed, fuck this shit, school doesn't start till monday. |
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i don't have a calculator or a sheet of paper or anything in front of me, but the first one 77.5 g? |
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you got it handoverthecart! =) |
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i could have resolved it two years ago i guess... but i forgot it all =/ |
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my study is physics, not chemistry....sorry.... |
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if i were paid a turntable i might consider calculating this shit |
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six |
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:D Are these the other ones? (im not sure :\ ) b) 6.26 g c) 19.35 g |
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b) correct c) correct props. you know your shit |
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Equation Work a. 2.5 moles of Na (2moles of Na2O/4 moles of Na = 1.25 moles of Na2O 1.25 moles of Na2O (62 grams of Na2O/1 mole of Na2O) = 78 grams of Na2O b. 18g of Na (1 mole of Na/ 23 grams of Na) = .782 moles of Na .782 moles of Na (1 mole of O2/4 moles of Na) = .195 moles of O2 1.95 moles of O2 (32 grams of O2/1 mole of O2) = 6.25 grams of O2 c. 75g of Na2O (1 mole of Na2O/62grams of Na2O) = 1.20 moles of Na2O 1.20 moles of Na2O (1 mole of O2/2moles of Na2O) = .60 mole of O2 .60 moles of O2 (32 grams of O2/1 mole of O2) = 19.3 grams |
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I got a C in chemistry. Never could quite grasp it. Did well in physics, though. |
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he's letting you do his homework |
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Why, in the name of Greek buggery, would I want to calculate that? |
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exactly |
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jesus that was HARD to read all the way thru... I know NONE of that stuff, I took one course of Chemistry in high school (summer school no less) and was stoned everyday.... All that is SO FOREIGN to me. |
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I took a chemistry class about this but got bad grades I think plus don't remember. |
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chemistry is fun ]=) |
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six |
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six |
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